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3n^2+5n-112=0
a = 3; b = 5; c = -112;
Δ = b2-4ac
Δ = 52-4·3·(-112)
Δ = 1369
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1369}=37$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-37}{2*3}=\frac{-42}{6} =-7 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+37}{2*3}=\frac{32}{6} =5+1/3 $
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